Question

a battery of 9v is connected in the series with resistor of 0.2 ohms,0.3 ohms, 0.4 ohms, 0.5 ohmsबैटरी ऑफ 9 वोल्ट इस कनेक्टेड इन सीरीज विद रेजिस्टर्स आफ 0.2 ओम्स कमर 0.3 ​

Answer 1

Answer:

6.42 Amperes

Explanation:

Given :

• Resistors of 0.2 ohms, 0.3 ohms, 0.4 ohms and 0.5 ohms are connected in series combination

• A battery having potential difference or voltage of 9 volts is connected in series to it

To find :

• Current passing through the circuit

Equivalent resistance when resistors are connected in series = R1+R2+R3+R4+R5......

Equivalent resistance = 0.2+0.3+0.4+0.5

Equivalent resistance = 1.4 Ohms

Using the ohms law :

V=I×R

9=I×1.4

I=9/1.4

I=6.42 Amperes

The current flowing through the circuit is equal to 6.42 Amperes

More :

• Coulombs law = q=i×t

• 1/Equivalent resistance for parallel combination = 1/R1 + 1/R2 + 1/R3 + 1/R4 + 1/R5