A battery of e.m.f 15 volt and internal resistance 2 ohm is connected to two resistors of resistance 4 ohm and 6 ohm joined in series find electrical energy spent per minute in 6 ohm resistor
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Net resistance of the circuit = 4+6+2 ohm = 12 ohm
current drawn = V/R(net) = 15/12 = 5/4 A
Electrical Energy spent
= i²R* time
= 25/16 * 6 * 60
= 562.5 J
current drawn = V/R(net) = 15/12 = 5/4 A
Electrical Energy spent
= i²R* time
= 25/16 * 6 * 60
= 562.5 J
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