A battery of e.m.f 20V and internal resistance 0.2ohmes supplies a load taking 10A. Determine the p.d at the battery terminals and the resistance of the load
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If the p.d is V then
V = E - IR
=20v−10A×0.2Ω
=18v
If the resistance of the load is R then,
V = I R
R = 18 / 10
=1.8Ω
hope it will help you.....
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