A battery of e.m.f 6 V and internal resistance 2 ohm is connected in parallel with another battery of e.m.f. 5 V and internal resistance 2 ohm. The combination is used to send current through an external resistance of 8 ohm. Calculate the current through the external resistance.
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Explanation:
Given,
E=−6 V,r=2Ω and i=1.5 A
We know that, current across a circuit,
i=
r+R
E
⇒15=
2+R
6
⇒2+R=
15
6
or R=4−2=2Ω.
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