A battery of EMF 10 V, with internal resistance 1
Ω is being charged by a 120 V d.c. supply using a
series resistance of 10 Ω. The terminal voltage of
the battery is
Answers
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0
Answer:
E=8V, internal resistance R
1
=0.5Ω
V=120V, resistance R
2
=15.5Ω
Effective voltage V
′
=V−E=112 V
I=
R
1
+R
2
V
′
=7 A
Voltage across R
1
=IR
1
=3.5 V
Terminal voltage =8+3.5=11.5 V
Series resistor in the charging circuit limits the current drawn from the external source.
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