A battery of emf 10v and internal resistance 3 ohms is connected to a resistor. if the current in the circuit is 0.5 a , find the resistance of the resistor and terminal voltage of battery
Answers
The resistance of the battery is 17 ohms and the voltage is 8.5 V
Explanation:
- emf of battery=10 v
- Internal resistance of battery "r" =3 ohms
- Current in the circuit "I" = 0.5 A
- Resistance of the resistor = R
- According to Ohm's law
I = E/(R+r)
R=17 ohms
Terminal voltage of the resistor = V
Ohm's law states that
V=I x R
V = 0.5 x 17
V= 8.5 V
Thus the resistance of the battery is 17 ohms and the voltage is 8.5 V
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A current of 5 amperes flows through a wire whose ends. Are the at a potential difference of 3 volts. Calculate the resistance of the wire ?
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Explanation:
Emf of batter,
Internal resistance of the battery,
Current in the circuit,
Resistance of the resistor =
The relation for current using ohm's law is
According to Ohm's Law
Hence the resistance of the resistors is and the terminal voltage is