Question

a battery of emf 10V, with internal resistance 1 ohm is being charged by a 120 DC supply using a series resistance of 10 ohm. the terminal voltage of the battery is​

Answer 1

Answer:

20 v

Explanation:

10 is being charged resistance by terminal battery is 20 v

Answer 2

Answer:

The correct answer is Option 3.

Explanation:

Equivalent emf in the circuit,

$V=E_{1} -E_{2}$

   = 120-10

   = 110V

Equivalent resistance in the circuit,

$R=R_{1} +R_{2}$

   = 10+1

   = 11Ω

Current in the circuit,

$I=\frac{V}{R}$

  = 110/11

  = 10A

The terminal voltage of the battery $=E_{2}- IR_{2}$

                                                           = 10-10×1

                                                           = 0V

So, the terminal voltage of the battery is equal to zero volts.

Hence, option 3 is correct.