Question

A battery of emf 12 V and internal resistance 0.5 is
connected to resistance of 0.5 Q the P.D. across the
resistors
(A) 1.2 volt
(B) 1.1 volt
(C) 1.05 volt
(D) 1 volt​

Answer 1

Answer:

6v

Explanation:

Here E =12v

We know in a circuit E=V+IR

so V=E - IR

here I= E/(r+R) ; r internal resistance

R external resistance

So I= 12/(0.5+0.5)

= 12A

So V= 12 - 12×0.5

=6