Question

A battery of emf 15V, a 3 ohm is connected in series to two resistors 3 ohm and 6 ohm connected in parallel. Find:-
a) the current through the battery
b) the current in 3 ohm resistor
c) the current in 6 ohm resistor
*(pls solve it I'll mark u as the brainliest)*​

Answer 1

GIVEN:-

emf = 15V

3 ohm and 6 ohm are connected in series with 3 ohm in parallel.

To Find:-

a) the current through the battery.

b) the current in 3 ohm resistor.

c) the current in 6 ohm resistor.

SOLUTION:-

Let's first calculate the parallel resistance.

$\large\Longrightarrow{\sf{\frac{1}{R}=\frac{1}{3}+\frac{1}{6}}}$

$\large\Longrightarrow{\sf{\frac{1}{R}=\frac{2+1}{6}}}$

$\large\Longrightarrow{\sf{\frac{1}{R}=\frac{3}{6}}}$

By doing reciprocal in both sides,

$\large\Longrightarrow{\sf{R=\frac{6}{3}}}$

$\large\red\therefore\boxed{\sf{\red{Parallel\:Resistance=2\:ohm}}}$

____________________________

Now the resistance in series.

$\large\Longrightarrow{\sf{R=2+3}}$

$\large\red\therefore\boxed{\sf{\red{Series\:Resistance=5\:ohm}}}$

____________________________

a)) the current through the battery.

$\large\Longrightarrow{\sf{V=IR}}$

$\large\Longrightarrow{\sf{I=\frac{V}{R}}}$

$\large\Longrightarrow{\sf{I=\frac{15}{5}}}$

$\large\blue\therefore\boxed{\sf{\blue{Current\:through\:the\:battery=3\:ampere}}}$

____________________________

b)) the current in 3 ohm resistor.

$\large\Longrightarrow{\sf{I=\frac{V}{R}}}$

$\large\Longrightarrow{\sf{I=\frac{15}{3}}}$

$\large\pink\therefore\boxed{\sf{\pink{Current\:in\:3\:ohm\:resistor=5\:ampere}}}$

____________________________

c)) the current in 6 ohm resistor.

$\large\Longrightarrow{\sf{I=\frac{V}{R}}}$

$\large\Longrightarrow{\sf{I=\frac{15}{6}}}$

$\large\green\therefore\boxed{\sf{\green{Current\:in\:6\:ohm\:resistor=2.5\:ampere}}}$

Answer 2

Explanation:

srijaqueen is right please mark her brainliest