Question

A battery of emf 2v and internal resistance is 0.5ohm .the maximum power transferred to the load is 0.05w.then find the current passing through the battery

Answer 1

v=IR


I=v/R


l=2/0.5


l=0.25

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Answer 2

Answer: 2A

Explanation: The condition for maximum power transmission is R = r i.e, external resistance is equal to internal resistance.

R = r = 0.5 ohm

EMF E = 2V

Current through the battery I = E / (R+r)

= 2/ ( 0.5+0.5)

= 2 / 1

= 2 A