Question

A battery of emf 2v sends a current of 0.5a through a coil for 1 minute ,then the electrical energy consumed is

Answer 1

Given ,

• Potential difference (v) = 2 v
• Current (I) = 0.5 Amp
• Time (t) = 1 min or 60 sec

As we know that ,

The product of potential difference and current is called electric power

The electric power denoted by " P "

P = VI -- (i)

and

The rate at which electric energy is consumed in a circuit is called electric power

P = Electric energy/t -- (ii)

From eq (i) and eq (ii) , we obtain

Electric energy = VIt

Substitute the known values in above formula , we get

$\sf \Rightarrow Electric \: energy = 2 × 0.5 × 60 \\ \\ \sf \Rightarrow</p><p>Electric \: energy = \cancel{2} × \frac{5}{ \cancel{10}} \times 60 \\ \\ \sf \Rightarrow Electric \: energy = \frac{\cancel5}{\cancel5} \times 60 \\ \\ \sf \Rightarrow Electric \: energy = 60 \: \: joule$

$\therefore \bold{ \sf \underline{The \: electric \: energy \: is \: 60 \: joule }}$