a battery of emf 3v is connected in series with 10ohm and with a parallel combination of resistances of 3ohm and 6ohm calculate i) resistance of parallel combination ii) current in the circuit
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Answer:
R=12Ω
I=0.25A
Explanation:
V=3v
R1=10Ω
R2=3Ω
R3=6Ω
R=?
I=?
1/R'=1/R2+R3
1/R'=1/3=1/6
1/R'=1/2
R'=2Ω
R=R1+R'
R=10+2
R=12Ω
V=IR
3=I*12
I=3/12
I=0.25A
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