Question

a battery of emf 4 volts and internal resistance 1 ohms is connected in parallel with another battery of emf 1 V and internal resistance 1 ohms (with their like poles connected together) The combination is used to send current through an external resistance of 2 ohms. calculate the current through the external resistance​

Answer 1

Explanation:

V 1 =4v

R 1=1Ω

V 2 =1v

R 2 =0Ω

'Total current from the combination=current flowing 2Ω=I

∴I= R 1 −R 2

v 1 −v 2 = 1+0

4−1 A=3A

Potential difference across 2Ω=(3×2)v

=6v

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