) A battery of emf 6 V and internal resistance 2 Ω is connected in parallel with another battery of emf 5 V and internal resistance 2 Ω . The combination is used to send a current through an external resistance of 8 Ω . Calculate the current through the external resistance
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Explanation: A battery of emf 4 volts and internal resistance 1Ω is connected in parallel with another battery of emf 1 volt Combination is used to send current through an external resistance 2Ω. Calculate current through external resistance and potential difference across external resistance.
equation: V
1
=4v
R
1
=1Ω
V
2
=1v
R
2
=0Ω
'Total current from the combination=current flowing 2Ω=I
∴I=
R
1
−R
2
v
1
−v
2
=
1+0
4−1
A
=3A
Potential difference across 2Ω=(3×2)v
=6v
i hope this works
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