Physics, asked by architamk02, 10 months ago

) A battery of emf 6 V and internal resistance 2 Ω is connected in parallel with another battery of emf 5 V and internal resistance 2 Ω . The combination is used to send a current through an external resistance of 8 Ω . Calculate the current through the external resistance

Answers

Answered by zai908494
0

Answer:

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Explanation: A battery of emf 4 volts and internal resistance 1Ω is connected in parallel with another battery of emf 1 volt Combination is used to send current through an external resistance 2Ω. Calculate current through external resistance and potential difference across external resistance.

equation: V

1

=4v

R

1

=1Ω

V

2

=1v

R

2

=0Ω

'Total current from the combination=current flowing 2Ω=I

∴I=

R

1

−R

2

v

1

−v

2

=

1+0

4−1

A

=3A

Potential difference across 2Ω=(3×2)v

=6v

i hope this works

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