Question

A battery of emf 6 v and internal resistance 2ohm is connected in parallel with another battery of emf 5v and internal resistance 2ohm the combination is used to send current through an external resistance of 8ohm what is the current through the external resistance

Answer 1

Answer:

Explanation:

Since the batteries are connected in reverse polarities, the net potential applied to the circuit =8V−4V=4V

The net resistance in the circuit =R+r  

1

​

+r  

2

​

 =9Ω+1Ω+2Ω=12Ω

Hence, the current in the circuit =  

12Ω

4V

​

 =  

3

1

​

A

Potential difference across P and Q =IR =  

3

1

​

A×9Ω =3V