A battery of emf E drives a current of 0.25A when connected to 5.5ohm resistor. When the 5.5 ohm resistor is replaced with 2.5ohm resistor, the current flowing becomes 0.5A. Find the emf E and the internal resistance r of the battery
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Answer:
r = 0.5 Ω
E = 1.5 V
Explanation:
MAKE TWO EQUATIONS USING FORMULA
E - I r = I R
Here,
r = internal resistance
R = external resistance
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