Question

a battery of two cells is used to light a torch bulb of resistance 5 ohm the cells maintain a potential difference of 3 volt across the bulb how much current will flow through the bulb

Answer 1

R = 5 ohm
V = 3 volt

V = IR ( ohm's law)
I = 3\5 = 0.6 A

Hope it helps!!

Answer 2

Hi dear,
V=3v
R=5oh!ms
V=IR
I=V/R
=3/5
=0.6A
current flown is 0.6 amps.
Hope it helps hoping for BRAINLIEST
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