a battery sets up an electric field of 25 N/C inside a uniform wire of length 2m and a resistance of 5 ohm . find current through the wire.
Answers
Answered by
23
R= 5 ohms
L= 2m
E= 25 N/C
using ohms law V=IR
I =V/R
V=ed
V= 25×2= 50V
since L is 2m so d=2 because electrons have to cover that distance.
I=50/5
=10A
L= 2m
E= 25 N/C
using ohms law V=IR
I =V/R
V=ed
V= 25×2= 50V
since L is 2m so d=2 because electrons have to cover that distance.
I=50/5
=10A
Answered by
7
Hey dear,
◆ Answer-
I = 10 A
◆ Explanation-
# Given-
E = 25 N/C
d = 2 m
R = 5 ohm
# Solution-
Potential difference is calculated by -
V = E.d
V = 25 × 2
V = 50 V
Current flowing through wire is -
I = V/R
I = 50/5
I = 10 A
Therefore, current flowing through wire is 10 A.
Hope it helps...
◆ Answer-
I = 10 A
◆ Explanation-
# Given-
E = 25 N/C
d = 2 m
R = 5 ohm
# Solution-
Potential difference is calculated by -
V = E.d
V = 25 × 2
V = 50 V
Current flowing through wire is -
I = V/R
I = 50/5
I = 10 A
Therefore, current flowing through wire is 10 A.
Hope it helps...
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