A battery supplies a current of .9a through 2ohm resistor and a current of .3a through 7ohm resistor then calculate emf and internal resistance of battery
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A cell supplies a current of 0 3 A through a resistance of 7 ohm and a current ... Suppose the internal resistance=r. Then, for 7 ohm resistance I=V/(R+r)=V / (7+r )=0.3 A. V=(7+r) x 0.3----(i). For 2 ohm resistance,I=V / (2+r)=0-9 A.
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