Question

A battery X of e.m.f.6 V and internal resistance 2 ohm is in series with a battery Y of e.m.f. 4 V and internal resistance 8 ohm so that the two e.m.f. acts in the same direction. A 10 ohm resistor is connected to the batteries. Calculate the terminal p.d. of each battery. If Y is reversed so that the e.m.f. s now oppose each other, what is the new terininal p.d. of X and Y?​

Answer 1

Answer:

total resistance=10 ohm. Current= (6-4)/10= .4 amp.

voltage drops on internal=.4*2=.8 for X

= .4*4=1.6 for Y

Now polarity. Because current is reversed in X, terminal voltage=4+.8

terminal voltage on Y= 6-1.6 Volts