Question

A battle ship is moving with velocity 10
m/s. A gun is mounted on the ship so as
to point straight backwards and is set at
an angle of elevation a@ for which range is
maximum. If velocity of projection relative
to gun is 50 m/s, find a. (Answer in
degree)​

Answer 1

Answer: 45 degrees

Explanation:

Range = $u^{2}$ sin (2a) / g

$u^{2}$/g will be constant and sin (2a) will differ because of change in angle a

Maximum range will be when sin (2a) will be maximum

2a = 90 degrees will be when sin (2a) will be maximum

a = 45 degrees