Question

(a+bc) (a-bc) (a^2+b^2c^2)​

Answer 1

$(a+bc)(a-bc)(a^{2}+b^{2}c^{2}) \\= [a^{2}-(bc)^{2}](a^{2}+b^{2}c^{2})$

$\boxed { \pink { (x+y)(x-y) = x^{2} - y^{2} }}$

$= [a^{2}-(bc)^{2}](a^{2}+(bc)^{2}]$

$= (a^{2})^{2} - [(bc)^{2}]^{2}\\= a^{4} - b^{4}c^{4}$

Therefore.,

$\red {(a+bc)(a-bc)(a^{2}+b^{2}c^{2})}\green {=a^{4} - b^{4}c^{4}}$

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