Question

A beach ball is inflated to a volume of 25L of air at 15oC. During the afternoon, the volume increases by 1L. What is the new temperature outside?

Answer 1

26.52 degree Celsius

Explanation:

V1=25 L

V2=26 L

T1=15+273=288 K

V1/T1=V2/T2

25/288=26/T2

T2=26*288/25

=299.52 K

=26.52 degree celsius

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