Question

A Bead Of Mass m is attached to one end of a spring of natural length R And spring constant K = (√3+1)mg/R . other end of the spring is attached toa point A ON the vertical ring of radius R MAKING AN ANGLE OF 30 DEGREE WITH ITS CIRCUMFERENCE THE NORMAL REACTION AT THE BEAD WHEN THE SPRING IS ALLOWED TO MOVE FROM POINT A

Answer 1

"Answer: We know, x = 2R cos60 = 2RX ½ = R.

Again, L-x =root 3R- R = (root 3-1) R

Again the spring Force is Fs = k (L-x) = (root3+R) mg/R X (root 3-1)R -= 2mg and W = mg.

The normal projection of the spring force is = −2mg cos 60 = 2mg 1 2 = −mg.

The normal projection weight is = mg sin 60 = mg √3/2 2.

Again the total of all forces should be zero. So N – mg + mg√3/ 2 = 0

Therefore N = (1- √3/ 2) mg

"