Question

A bead starts sliding from a point P on a frictionless wire initial velocity of 5ms^-1.Find the velocity of bead at point R (take g=10)

Answer 1

Answer:

6 root 2 m/s

Step-by-step explanation:

Answer 2

Answer:

The velocity of bead at point R  is $V_{2}$ = 8.48 m/s

The wire was frictionless so no loss against friction.

Step-by-step explanation:

From the above question,

They have given :

A bead starts sliding from a point P on a frictionless wire initial velocity of 5m$s^{-1}$

Let x be the distance between points P and R.

he velocity of the bead at point R

Fall in height = 4 - 1.65

                     = 2.35 m

As the wire is frictionless, the bead will only experience the acceleration due to gravity. So, the velocity of the bead at point R will be

                v = v0 + gt

where v0 is the initial velocity, g is the acceleration due to gravity and t is the time taken for the bead to reach point R.

We need to calculate the time taken for the bead to reach point R. Let's say the distance between point P and point R is x.

                t = x / v0

So gain in K.E will be loss in PE

                K$E_{2}$ = K$E_{1}$  +  Δ PE

               K.$E_{2}$ = K , $E_{1}$ + mgh

               K,$E_{2}$ = $\frac{1}{2}$ mv $\frac{2}{1}$ + mgh

           $\frac{1}{2}$  mv $\frac{2}{2}$ = $\frac{1}{2}$ mv $\frac{2}{1}$ + mgh  

                   $V_{2}$ = $\sqrt{V_{1}^{2} + 29h }$

                   $V_{2}$ = $\sqrt{25+2*10*2.35}$

                   $V_{2}$ = 8.48 m/s

The wire was frictionless so no loss against friction.

For more such related questions : https://brainly.in/question/12556220

#SPJ2