a beaker a solution is made by dissolving 2 to 3
crystals of potassium permanganate in 100 ml of water in litres of the solution is added in another be copy and the volume is made 100 ml by adding water same process repeated again by taking 10 ml of solution from the beaker b2c and subsequently from speaker c2d the solution with the least concentration is
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the solution with the least concentration is d2e
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This is a typical case of series dilution.
As per question one must notice the initial amount of potassium parmanganate is constant.
When 10ml from beaker A is taken into beaker B; as the solution in beaker A was homogenous, part of potassium parmanganate came into beaker B is actually 1/10th of the total parmanganate amount.
Same procedure is followed upto beaker D. Thus mathematically beaker D contains 1/1000 amount of parmanganate present in beaker A = 1/100 amount of parmanganate present in beaker C = 1/10 amount of parmanganate present in beaker B, thus containing the least parmanganate concentration.
Beaker D has the solution with least concentration.
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