Question

A beaker containing a liquid of density rho moves up with an acceleration a. The pressure due to the liquid at a depth h below the free surface of the liquid is.

Answer 1

Answer:

hello mate..

here's your answer..

Pressure = hpg

In this case g = a+g

= a+gTherefore, P= hp(g+a).

= a+gTherefore, P= hp(g+a).Hope it helps.....♡

Answer 2

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Correct option (c) h ρ (g + a)

Explanation:

When a beaker containing a liquid of density r moves up with an acceleration a, it will work as a lift moving upward with acceleration a. The effective acceleration due to gravity in lift = (a + g) Pressure of liquid of height h = h ρ (a + g)