A beaker containing water weighs 100 g. It is placed on the pan of a balance and a piece of metal weighing 70 g and having a volume of 10 cm3 is placed inside the water in the beaker. The weight of the beaker and the metal would be
Answers
Answered by
1
Answer:
Archimedes principle states that loss in weight of the body = weight of the volume displaced by it
Archimedes principle states that loss in weight of the body = weight of the volume displaced by it so we can easily say that Weight of the beaker and the metal = 170gm
Explanation:
please mark me in brainly list
Similar questions