A beaker contains 200 gm of water.the heat capacity of the beaker is equal to that
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✳hy✴
✳here is your answer ✴
Heat lost by hot water = Heat gained by cold water in beaker + Heat absorbed by
440(92−θ)=200×(θ−20)+20×(θ−20)
Þ
T=68∘C
✳here is your answer ✴
Heat lost by hot water = Heat gained by cold water in beaker + Heat absorbed by
440(92−θ)=200×(θ−20)+20×(θ−20)
Þ
T=68∘C
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