Question

a beaker contains 9g of water .
the no of H atoms are?​

Answer 1

Water has 18 grams per mole so 9 grams is 0.5 moles of water. There are 6.022* 10^23 molecules in a mole. Each water molecule contains *one* oxygen and *two* hydrogens. in 9 grams of water.

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Answer 2

Answer:

9.033 * 10^23 atoms

Explanation:

nine is half of 18, which means that half mole is found in nine g of water. half * 6.022 *10^23 = 3.011 * 10^23 molecules H2O.

However, in case you need to realize what number of ATOMS are found in 3.011 *10^23, you should then multiply via way of means of 3 (2 hydrogen atoms and 1 oxygen atom consistent with molecule), and get 9.033 * 10^23 atoms.

So, the final answer is 9.033 * 10^23 H  atoms are in 9g of water.

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