A beaker contains a liquid of density 'p' upto
height 'h', such that 'P' is atmospheric pressure
and 'g' is acceleration due to gravity. Answer
(a) What is the pressure on the free surface of liquid ?
(b) What is the pressure on the base of beaker?
the following questions :
liquid?
(c) What is the lateral pressure at the base on
the inner walls of beaker?
Answers
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3
Answer:
(a) Pressure at free surface of liquid is the atmospheric pressure itself since P=P
A
+ρgh and for height =0, the pressure P =P
A
.
(b) At the base of the beaker of height h and density of liquid ρ, the pressure P=P
A
+ρgh
(c) Since the pressure exerted on the lateral walls is balanced by a normal reaction by walls onto the liquid, these forces must be equal and since pressure in fluids acts equally in all the directions, thereby implying P=P
A
+ρgh
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