Question

A beaker contains water upto a height of 10 m what is the pressure at the bottom if g =10 m/s2

Answer 1

Answer:

P = Po + hpg

Po = 10^5 Pa

h = 10m

p = density of water = 1000kg/m^3

g = 10m/s^2

P = 10^5 Pa + (10*10^3*10) = 2*10^5 Pa

P = 2*10^5 Pa