Question

A beaker has 1 litre of water. Raju draws water from the beaker in several steps that
follow a certain pattern. To begin with, he draws one-half of the water in the beaker.
He then draws one-third of the remaining water in the beaker. Finally, he draws one-
fourth of the remaining water in the beaker. How much water did Raju remove from
the beaker in these three steps?​

Answer 1

Answer:

417 in first step, 333 in 2 nd step, and 250 ml in third step

Step-by-step explanation:

1/4 of 1000 ml is 250 ml

1/3 of 1000 ml is 333 ml

sum of 333&250 is 583

1000

-583

= 4 1 7 ml

Answer 2

Answer:

$\huge\mathbb\fcolorbox{purple}{lavenderblush}{✰Answer}$

Step-1

He removes $\tt \: \frac{1}{2}$of the water from the beaker .

Amount of water remaining in beaker$\tt = \frac{1}{2}$

Step-2

Then he removed $\tt \frac{1}{3}$from the remaining water.

ஃ He removed $\tt \frac{1}{3} \: of \: \frac{1}{2} = \frac{1}{3} \times \frac{1}{2} = \frac{1}{6}$

Amount of water remaining in beaker$\tt= \frac{2}{3} of \: \frac{1}{2} = \frac{2}{3} \times \frac{1}{2} = \frac{1}{3}$

Step-3

Then he removed $\tt \: \frac{1}{4}$

From the remaining water

ஃ‍He removed $\tt\frac{1}{4} of \: \frac{1}{3} = \frac{1}{4} \times \frac{1}{3} = \frac{1}{12}$

total water he removed,

$\tt= \frac{1}{2} + \frac{1}{6} + \frac{1}{12} \\ \\ = \tt\frac{6 + 2 + 1}{12} \\ \\ \tt = \frac{9}{12} = \frac{3}{4}$

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