Math, asked by anindyajana, 2 months ago

A beaker has 1 litre of water. Raju draws water from the beaker in several steps that
follow a certain pattern. To begin with, he draws one-half of the water in the beaker.
He then draws one-third of the remaining water in the beaker. Finally, he draws one-
fourth of the remaining water in the beaker. How much water did Raju remove from
the beaker in these three steps?​

Answers

Answered by aditiaditi9964
0

Step-by-step explanation:

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Attachments:
Answered by ItzBlinkingstar
1

Answer:

\huge\mathbb\fcolorbox{purple}{lavenderblush}{✰Answer}

Step-1

He removes \tt  \:  \frac{1}{2}  of the water from the beaker .

Amount of water remaining in beaker\tt =  \frac{1}{2}

Step-2

Then he removed \tt \frac{1}{3} from the remaining water.

ஃ He removed \tt \frac{1}{3}  \: of \:  \frac{1}{2}  =  \frac{1}{3}  \times  \frac{1}{2}  =  \frac{1}{6}

Amount of water remaining in beaker \tt=  \frac{2}{3} of \:  \frac{1}{2}  =  \frac{2}{3}  \times  \frac{1}{2}  =  \frac{1}{3}

Step-3

Then he removed \tt \:  \frac{1}{4}

From the remaining water

ஃ‍He removed  \tt\frac{1}{4} of \:  \frac{1}{3}  =  \frac{1}{4}  \times  \frac{1}{3}  =  \frac{1}{12}

total water he removed,

\tt=  \frac{1}{2}  +  \frac{1}{6}  +  \frac{1}{12}  \\  \\  =  \tt\frac{6 + 2 + 1}{12}  \\  \\ \tt =  \frac{9}{12}  =  \frac{3}{4}

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