Question

A beaker is filled with two non-mixing liquids. The lower liquid has density twice that of the upper one. A cylinder of height h floats with 1/4th of its height submerged in the lower liquid and half of its height submerged in the upper liquid. Another beaker is filled with the denser of the two liquids alone. If the same cylinder is kept in the second beaker, the height of the submerged position would be

Answer 1

Answer:

Explanation:

Using Archimedes' principle, we get:

LAdg=(pL)A(nρ)g+(1−p)LAρg

⇒d=(1−p)ρ+(pn)ρ

        =[1+(n−1)p]ρ

Answer 2

Answer:

option c-h/2 is the answer!!!