Question

A BEAKER IS FULL OF A FLUID , AND A SOLID OBJECT FROM A CERTAIN HEIGHT IS DROPPED IN THE FLUID , IF THE DENSITY OF FLUID AND THE SOLID OBJECT ARE EQUAL , THEN STATE WHAT WILL HAPPEN NEXT , IF THE SOLID IS DISSOLVABLE IN FLUID

DEAL WITH EVERY CONSEQUENCES SUBSEQUENTLY

EVERY CONSEQUENCES INCLUDES IDEAL AND PRACTICAL CASES , MAYBE HYPOTHETICAL OR REALISTIC , BUT SHOULD EXTENT TO POSSIBILITIES

Answer 1

Hey there!
Awesome question to answer.

Really, Now one observes what's the science behind this. Many times we drop solids in fluids. But did we think what happens?

So, Come on, we shall know what happens.



The Fluid get displaced equal to the weight of the solid object. Let's take the weight of Solid is N. Hence, N weighing fluid is to be displaced. Once The solid is half dropped. The half of volume of the fluid [ N /2] gets out of the container. Then the rate of dissolving of solid starts.It will be inversely proportional to square of rate of fluid thrown out.

As we are given the privilege of deal with hypothetical conditions. Consider that the beaker is taken to the polar regions. The fluid will start to solidify and the solid which is being dropped from a certain height will remain on the surface of the fluid which is solidified.

Consider we have made the conditions go beyond the boiling point of fluid. The fluid will absolutely start to become vapour. Hence, The chances of solid clubbing with fluid will be inversely proportional root of the fluid conversion to gas. As if the fluid is slowly converting, the solid will get into the fluid, try to displace some amount of it. If the conversion goes on a speed way, the solid will remain alone in the beaker.

Consider, I have taken the beaker and solid to vacuum. I have taken the beaker tightly closed. Once, I reach space. I will open the knob of the beaker, the solid is the dropped in the next instant. We know that objects float in space due to absence of gravity. The fluid will come out of the beaker and float in the space, so is the solid.

Consider the fluid is elastic. The fluid can resist the solid piece. If the solid piece is dropped. The fluid has the energy to push the solid in upward direction. This is cancelled by existing gravity.the solid will bounce, each time it bounces the fluid Energy decreases. The solid renounces till some times and after some numbers of rebounces it will stay float on the the fluid.

Consider the beaker is made of some synthetic material which gets melted very quickly. And we increase the temperature. The fluid starts to evaporate. The beaker also melts. So, The solid will either reach the surface on which beaker is placed or get evaporated.

Hope my answer helped you! ^^

Answer 2

Condition no 1
NONE other than your own bedroom
I hope this is brainly.in so indian right the temperature in India doesn't show gradual changes suppose you are at 25°c.
When the ball will fall in the beaker the same amount of water will flow from it and the ball or the object will be totally in the water just below the surface.
2. Condition : TRY it on the moon
Before the ball drops down the water will start boiling causing decrease in density as compared to solid object also the force would be too less as the acceleration is less
So it will take much time to go down. There is lot of water blown out
3. Condition : on the sun
It will have more increase in the amount of energy loss as the water will support burning now due to low pressure.