Question

A beaker of radius 10 cm is filled with water. Calculate the force of surface tension on any diametrical line on its surface. Surface tension of water is 0.075 N/m.​

Answer 1

$\huge\bf{\underline{\underline{Answer : -}}}$

Given,

L = 2 × 10 = 20 cm = 0.2 m

T = 0.075 N/m

We have,

• $\LARGE\sf\red{T = \frac{F}{L}}$

∴F = TL = 0.075 × 0.2 = 0.015

=$\large\sf\red{\fbox{\fbox{1.5 × 10^-\:^2 N}}}$

Answer 2

Given:

                   The radius of the beaker(L) = 10 cm

            The surface tension of water(T) = 0.075 N/m.

To Find:

             Force of the Surface Tension

Solution:

The force of surface tension can be calculated by the formula,

                                             $T=\frac{1}{2} *\frac{F}{L}$

Here, $T$ is the Surface Tension,

         $F$ is the Force of the Surface Tension,

And, $L$ is the length of the Surface.

Since the units of radius and the surface tension are different. So,

The radius of the beaker = $\frac{10}{100}$

                                         $=0.10 m$

Now, By putting the values,

                                         $0.075 = \frac{1}{2} * \frac{F}{0.10}$

                                         $0.075 = \frac{F}{0.20}$

                               $0.075*0.20=F$

                                         $0.015 = F$

It can also be written as $1.5*10^2$.

So, the Force of the Surface Tension is 1.5 *10².