Question

A beaker when partly filled with water has total mass 20.00g. If a piece of metal with density 3.00g//cm^(3) and volume 1.00cm^(3) is suspended by a thin string, so that it is submerged in the water but does not rest on the bottom of the beaker, how much dies the beaker then apper to weigh if it is resting on a scale?

Answer 1

Hence the weight of the beaker is 0.206 N

Explanation:

Given data:

• Mass of water = 20 g = 20 x 10^-3 kg
• Density of metal = 3.00 g / cm^3
• Volume of metal = 1.00 cm^3

Solution:

Reading =weight of water + magnitude of upthrust on piece of metal (acting downwards)

= (0.02 × 9.8) + (10^− 6)(10^3)(9.8)

= 0.206 N.

Hence the weight of the beaker is 0.206 N