A beaker with a liquid of density 1.4 g cm⁻³ is in balance over one pan of a weighing machine. If a solid of mass 10 g and density 8 g cm⁻³ is now hung from the top of that pan with a thread and sinking fully in the liquid without touching the bottom, the extra weight to be put on the other pan for balance will be(a) 10.0 g(b) 8.25 g(c) 11.75 g(d) –1.75 g
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ans c this is weite ok
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The the extra weight to be put on the other pan for balance will be 1.75g
Density of the liquid = 1.4g (Given)
Mass = m = 10g (Given)
Density of the mass = 8g (Given)
Volume of the solid mass = Mass of solid / Density of solid
= 10/8
= 5/4
Thus, volume is 5/4 g/cm³
Volume of the liquid = 5/4 ( as the solid will displace the liquid in its own volume)
Mass of the liquid = Volume × density of liquid displaced
= 5/4 × 1.4
= 1.75g
Thus, the extra weight needed is 1.75g.
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