Question

A beam AB 10 m long is simply supported at its ends A and B. It carries a uniformly

distributed load of 20 kN/m for a distance of 5 m from left end A and a concentrated load of

40 kN at a distance of 2 m from the right end B. Draw Shear Force and Bending Moment

diagram for the beam​

Answer 1

Answer:

ANSWER

Given that,

Mass m=10 kg

Inclination angle α=30

0

Friction coefficient μ=0.5

Normal reaction, N=mgcosα

Friction force,F

f

=μN=μmgcosα

Net pulling force, F=F

r

+mgsinα

F=μmgcos30

o

+Mgsin30

o

F=0.5×10×9.8×

2

3

+10×9.8×

2

1

=91.4N

Hence, the pulling force is 91.4 N