Question

A beam of helium atoms moves with a velocity 2×10^-4ms^-1.Find the wavelength of particles constituting with the beam.

Answer 1

Answer:

mis the wavelength of the beam

Explanation:

According to de Broglie's equation

λ= h/m×v

where,

λ=wavelength

h=plank '=6.626×10^−34 kgm2/s

m=mass

Mass of helium atom =4amu.

Convert amu into kg as follows

4amu× 1g/6.022×10^23amu

=0.664×10 ^−23g

=6.64×10^−27 kg

Putting the values in the above equation as follows.

6.626×10^−34 kgm^2/s /6.64×10^−27 kg×2×10^4m/s

=0.498×10^−7m

Thus, 0.498×10^−7mis the wavelength of the beam

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