Physics, asked by namitasar, 7 months ago

A beam of ions with velocity 2×10^5 m/s enters normally into a uniform magnetic field of 0.04 tesla. If the specific change of ions is 5×10^7 c/kg. Find the radius of the circular coil.

Answers

Answered by shaikhiqra467

2

Explanation:

Radius of circular path is given as r=

qB

mv

=

(q/m)B

v

putting as it is values we get r=1meter

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