Question

A beam of light consisting of three rays - P, Q, R is incident on a transparent plastic block



from air as shown in the figure below.

Which of the following statements is true?

A. Refractive index for P is greater than that for Q.

B. Refractive index for P is greater than that for R.

C. Refractive index for R is greater than that for Q.

D. Refractive index for P, Q and R is the same

40c529031dd352f7f363fe853dee5e28.docx

Answer 1

Answer:

d is the answer

Explanation:

hope it helps you

Answer 2

Option C : Refractive index for R is greater than that of P and Q

Refractive Index :

• Refractive index shows the measure of the bending of a light ray when it crosses from one medium to another.
• It is denoted by the symbol "n"
• It can be formulated using the angle of incidence "i" with the normal in one medium and the angle of reflection "r" with the normal in the other medium as :

                       $n = sin(i)/sin(r)$

In the figure given in the attached document, for the 3 rays (P, Q and R) the angle of incidence i.e. "i" is same.

Thus,      

                     $i_{P} =i_{Q} =i_{R}$

                  $sin(i_{P} )=sin(i_{Q} )=sin(i_{R} )$

But the angle of refration in the given figure for the rays P, Q and R are different with the normal :

                  $r_{P} = r_{Q} > r_{R}$

                 $sin(r_{P} ) = sin(r_{Q} ) > sin(r_{R} )$

                 $1/sin(r_{P} ) = 1/sin(r_{Q} ) < 1/sin(r_{R} )$

                $sin(i_{P})/sin(r_{P} ) = sin(i_{Q})/sin(r_{Q} ) < sin(i_{R})/sin(r_{R} )$

                $n_{P} =n_{Q} < n_{R}$

Hence, the refractive index for the ray R is the greatest and the index for P and Q are smaller and equal.

             

To lear more about Refractive Index, visit

https://brainly.in/question/3306087

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