A beam of light converges at a point P. Now a lens is placed in the path of the convergent beam 12cm from P. At what point does the beam converge if the lens is (a) a convex lens of focal length 20cm, and (b) a concave lens of focal length 16cm?
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Answer:
Here , the point P on the right of the lens acts as a virtual object
u=12 cm , v=?
(a) f=20cm
As
1/f =1/v -1/u
1/v -1/12= 1/20
1/v =1/20 +1/12= 8/60
v=60/8= 7.5cm
Image is at 7.5 cm to the right of the lens where the beam converges.
(b) f= -16cm , u=12 cm
As,
1/f =1/v -1/u
1/v= 1/f +1/u = -1/16 +1/12
= 1/48
v= 48cm
Hence image is at 48cm to the right of the lens, where the beam would converge.
Hope this helps!
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