Question

A beam of light of wavelength 600 nm from a distance source falls on a single slit 1 mm wide and the resulting diffraction pattern is observed on a screen 2m away. The distance between the first dark fringes on either side of the central bright fringe isA beam of light of wavelength 600 nm from a distance source falls on a single slit 1 mm wide and the resulting diffraction pattern is observed on a screen 2m away. The distance between the first dark fringes on either side of the central bright fringe isA beam of light of wavelength 600 nm from a distance source falls on a single slit 1 mm wide and the resulting diffraction pattern is observed on a screen 2m away. The distance between the first dark fringes on either side of the central bright fringe isA beam of light of wavelength 600 nm from a distance source falls on a single slit 1 mm wide and the resulting diffraction pattern is observed on a screen 2m away. The distance between the first dark fringes on either side of the central bright fringe is

Answer 1

Single slit experiment. 
Formula for fringe width = λ D / d
      slit width  d = 0.001 m = 1mm ,  
       λ = 600 nm  ,  D = screen distance = 2m
 
So fringe width = 600 nm * 2m /0.001 m   = 1.2 mm

DIstance between two dark fringes which are on either side of the central bright fringe = 2 * 1.2 mm = 2.4 mm

Answer 2

✴ola!!✴

refer to attachment ⤴⤴