Question

A beam of light travelling parallel to the principal axis of a concave lens appears to diverge from a point 25 cm behind the lens after refraction. Calculate the power of the lens.
Explain this with Solution.

Answer 1

Answer:

here the focal length of the lens will be -25cm= -0.25 m or $\frac{-25}{100}$ m

as it diverges from 25 cm and negative as it diverges from behind the lens

now Power = $\frac{1}{f}$ = $\frac{1}{-0.25}$ = $\frac{-100}{25}$ = -4

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