A beam of mixture of alpha particles and protons are accelerated through same potential difference before entering into a transverse uniform magnetic field of strength B as shown in the figure. If radius of one circular arc r1 = 10 cm, then r2 is (r2 > r1)
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refer to the image below^^
Answer:
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Brainly.in
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Secondary School Physics 13+7 pts
A beam of mixture of alpha particles and protons accelerated through same potential difference before entering into the magnetic field of strength
b. If r2= 5cm and then r1=
Ask for details Follow Report by Pjing4289 08.08.2019
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Maxwell1414
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QwtigerSamaritan
Answer:
The value of r1 is 5/√2
Explanation:
According to the problem the r2= 5 cm
Now, when we charge a particle q1 with voltage v then it gains energy
q1v= 1/2 mv^2
now the radius is r1= mv1/q1B
= p/q1B
= √2me1/q1B
= √2mq1V/q1B
= √m1/q1 . √2v/B
Similarly we can write, r2= √m2/q1.√2v/B
Now r2/r1= √m2/q1.√2v/B/ √m1/q1 . √2v/B
= √m2/q2 . √q1/m1
= √q1/q2 . √m2/m1
The mass of alpha particle is four times of proton particles
the charge of alpha particle is two times of protons particles
Therefore, r2/r1 = √4 x √1/2
=> √2 r1= r2
= >r1= 5/√2