Question

A beam of red light has an amplitude 2.5 times amplitude of second beam of the same colour: calculate the ratio of the intensities of the two waves

Answer 1

The ratio of the intensities of the two waves = 5.44

Given:

A beam of red light has an amplitude 2.5 times amplitude of second beam of the same colour.

That is $\frac{F_1}{F_2}$ = 2.5    $F_1$ = 2.5 $F_2$

To find:

The ratio of the intensities of the two waves.

Explanation:

Maximum intensity $I_{max}$=($F_1 +F_2$)²

Minimum intensity $I_{min}$ = ($F_1 -F_2$)²

$\frac{Maximum\ intensity }{minimum \ intensity}$ = $\frac{(F_1 +F_2)^2}{(F_1 -F_2)^2}$ = $\frac{(2.5F_2 +F_2)^2}{(2.5F_2 -F_2)^2}$  

                           = 2.33² = 5.44

The ratio of the intensities of the two waves = 5.44

It just ratio it has no unit.

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