Question

A beam of singly ionized (1+) lithium atoms (m ≈ 7mproton) is accelerated by a potential difference of 320 V. The beam passes through a magnetic field of 1.5×10−2 T. What is the radius of curvature of the beam in the magnetic field?

Answer 1

SOLUTION-;

• Answer
• 0
• boffeemadrid
• Given
• m = Mass of lithium ions =  
• B = Magnetic field = 0.015 T
• V = Potential difference = 320 V
• To find
• Radius of curvature of the beam = r
• Solution
• = Mass of proton =  
• Energy of beam
• Energy of particles
• So
• The magnetic force and centripetal force will balance each other
• The radius of the curvature of the beam in the magnetic field is  
• THANKS  
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