Question

A beam of singly ionized Lithium atoms is accelerated by a potential difference of 320 V. The beam passes through a magnetic
field of 0.015 T. What is the radius of curvature of the beam in the magnetic field?
O 0.50 m
0 0.25 m
O 0.74 m
O 0.45 m​

Answer 1

Answer:This may help you

Explanation:

Taken v ortogonal to v

on have

m v^2 / r = e v B

r = m v / (e B)

where

v = (2 e V / m)^1/2

then

r = (1 / B) (2 m V / e)^1/2

r = (1 / 0.015) * (2 * 11,52x10^-27 * 320 / 1.6x10^-19)^1/2 ~ 0.46 m